New PDF release: Artinian Modules over Group Rings

By Leonid Kurdachenko, Javier Otal, Igor Ya Subbotin

ISBN-10: 376437764X

ISBN-13: 9783764377649

ISBN-10: 3764377658

ISBN-13: 9783764377656

From the reviews:

“The idea of modules over team earrings RG for countless teams G over arbitrary jewelry R is a truly huge and intricate box of study with a good number of scattered effects. … because a number of the effects look for the 1st time in a publication it may be suggested warmly to any professional during this box, but additionally for graduate scholars who're offered the wonderful thing about the interaction of the theories of teams, earrings and representations.” (G. Kowol, Monatshefte für Mathematik, Vol. 152 (4), December, 2007)

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Therefore the union of any ascending chain of proper submodules of E cannot reach E itself. By Zorn’s Lemma, E has a maximal proper R-submodule V . In particular, E/V is a simple R-module. By (3), there is a submodule U such that A = V ⊕ U . Since V ≤ E, the modular law gives that E = V ⊕ (E ∩ U ). Since E/V ∼ = E ∩ U , E ∩ U is a simple R-submodule. In particular, S =SocR (A) = 0 . If S = A, then A = S ⊕ W for some R-submodule W . Again we choose an element 0 = w ∈ W , and consider the submodule wR.

I. Zaitsev [294] and only makes use of standard properties of divisible abelian groups. 11. Let G be a finite group and suppose that A is a ZG-module, and B is a ZG-submodule of A. If the underlying additive groups of A and B are divisible, then there exists a ZG-submodule E such that A = B + E and n(B ∩ E) = 0 , where n = |G|. In particular, if B is Z-torsion-free, then A = B ⊕ E. 12. Let G be a finite group. Suppose that A is a ZG-module and B is a ZG-submodule of A. If the underlying additive group of A is finitely generated, then there exists a ZG-submodule E such that B ∩ E and A/(B ∩ E) are finite.

Our next goal is to obtain some elementary properties of the class of XCgroups, when X is a formation of groups, which is a slight extension of the class F of finite groups. 5. Let G be a group, and suppose that G/C is an abelian Chernikov group, where C = ζ(G). Assume that H is a subgroup of G such that H ≥ C, H/C = h1 C · · · hn C and |hj C| = psj , where p is a prime and sj ∈ N for 1 ≤ j ≤ n. Then [G, H] is a finite p-subgroup of C, and rp ([G, H]) ≤ nrp (G/C). Proof. If 1 ≤ j ≤ n, we consider the mapping φj : G −→ C given by gφj = [g, hj ], g ∈ G.

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Artinian Modules over Group Rings by Leonid Kurdachenko, Javier Otal, Igor Ya Subbotin

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